3.137 \(\int \frac {a+b x^2+c x^4}{x^5 \sqrt {d-e x} \sqrt {d+e x}} \, dx\)

Optimal. Leaf size=126 \[ -\frac {\tanh ^{-1}\left (\frac {\sqrt {d-e x} \sqrt {d+e x}}{d}\right ) \left (3 a e^4+4 b d^2 e^2+8 c d^4\right )}{8 d^5}-\frac {\sqrt {d-e x} \sqrt {d+e x} \left (3 a e^2+4 b d^2\right )}{8 d^4 x^2}-\frac {a \sqrt {d-e x} \sqrt {d+e x}}{4 d^2 x^4} \]

[Out]

-1/8*(3*a*e^4+4*b*d^2*e^2+8*c*d^4)*arctanh((-e*x+d)^(1/2)*(e*x+d)^(1/2)/d)/d^5-1/4*a*(-e*x+d)^(1/2)*(e*x+d)^(1
/2)/d^2/x^4-1/8*(3*a*e^2+4*b*d^2)*(-e*x+d)^(1/2)*(e*x+d)^(1/2)/d^4/x^2

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Rubi [A]  time = 0.28, antiderivative size = 182, normalized size of antiderivative = 1.44, number of steps used = 6, number of rules used = 6, integrand size = 35, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.171, Rules used = {520, 1251, 897, 1157, 385, 208} \[ -\frac {\sqrt {d^2-e^2 x^2} \tanh ^{-1}\left (\frac {\sqrt {d^2-e^2 x^2}}{d}\right ) \left (3 a e^4+4 b d^2 e^2+8 c d^4\right )}{8 d^5 \sqrt {d-e x} \sqrt {d+e x}}-\frac {\left (d^2-e^2 x^2\right ) \left (3 a e^2+4 b d^2\right )}{8 d^4 x^2 \sqrt {d-e x} \sqrt {d+e x}}-\frac {a \left (d^2-e^2 x^2\right )}{4 d^2 x^4 \sqrt {d-e x} \sqrt {d+e x}} \]

Antiderivative was successfully verified.

[In]

Int[(a + b*x^2 + c*x^4)/(x^5*Sqrt[d - e*x]*Sqrt[d + e*x]),x]

[Out]

-(a*(d^2 - e^2*x^2))/(4*d^2*x^4*Sqrt[d - e*x]*Sqrt[d + e*x]) - ((4*b*d^2 + 3*a*e^2)*(d^2 - e^2*x^2))/(8*d^4*x^
2*Sqrt[d - e*x]*Sqrt[d + e*x]) - ((8*c*d^4 + 4*b*d^2*e^2 + 3*a*e^4)*Sqrt[d^2 - e^2*x^2]*ArcTanh[Sqrt[d^2 - e^2
*x^2]/d])/(8*d^5*Sqrt[d - e*x]*Sqrt[d + e*x])

Rule 208

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-(a/b), 2]*ArcTanh[x/Rt[-(a/b), 2]])/a, x] /; FreeQ[{a,
b}, x] && NegQ[a/b]

Rule 385

Int[((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_)), x_Symbol] :> -Simp[((b*c - a*d)*x*(a + b*x^n)^(p +
1))/(a*b*n*(p + 1)), x] - Dist[(a*d - b*c*(n*(p + 1) + 1))/(a*b*n*(p + 1)), Int[(a + b*x^n)^(p + 1), x], x] /
; FreeQ[{a, b, c, d, n, p}, x] && NeQ[b*c - a*d, 0] && (LtQ[p, -1] || ILtQ[1/n + p, 0])

Rule 520

Int[(u_.)*((c_) + (d_.)*(x_)^(n_.) + (e_.)*(x_)^(n2_.))^(q_.)*((a1_) + (b1_.)*(x_)^(non2_.))^(p_.)*((a2_) + (b
2_.)*(x_)^(non2_.))^(p_.), x_Symbol] :> Dist[((a1 + b1*x^(n/2))^FracPart[p]*(a2 + b2*x^(n/2))^FracPart[p])/(a1
*a2 + b1*b2*x^n)^FracPart[p], Int[u*(a1*a2 + b1*b2*x^n)^p*(c + d*x^n + e*x^(2*n))^q, x], x] /; FreeQ[{a1, b1,
a2, b2, c, d, e, n, p, q}, x] && EqQ[non2, n/2] && EqQ[n2, 2*n] && EqQ[a2*b1 + a1*b2, 0]

Rule 897

Int[((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))^(n_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :
> With[{q = Denominator[m]}, Dist[q/e, Subst[Int[x^(q*(m + 1) - 1)*((e*f - d*g)/e + (g*x^q)/e)^n*((c*d^2 - b*d
*e + a*e^2)/e^2 - ((2*c*d - b*e)*x^q)/e^2 + (c*x^(2*q))/e^2)^p, x], x, (d + e*x)^(1/q)], x]] /; FreeQ[{a, b, c
, d, e, f, g}, x] && NeQ[e*f - d*g, 0] && NeQ[b^2 - 4*a*c, 0] && NeQ[c*d^2 - b*d*e + a*e^2, 0] && IntegersQ[n,
p] && FractionQ[m]

Rule 1157

Int[((d_) + (e_.)*(x_)^2)^(q_)*((a_) + (b_.)*(x_)^2 + (c_.)*(x_)^4)^(p_.), x_Symbol] :> With[{Qx = PolynomialQ
uotient[(a + b*x^2 + c*x^4)^p, d + e*x^2, x], R = Coeff[PolynomialRemainder[(a + b*x^2 + c*x^4)^p, d + e*x^2,
x], x, 0]}, -Simp[(R*x*(d + e*x^2)^(q + 1))/(2*d*(q + 1)), x] + Dist[1/(2*d*(q + 1)), Int[(d + e*x^2)^(q + 1)*
ExpandToSum[2*d*(q + 1)*Qx + R*(2*q + 3), x], x], x]] /; FreeQ[{a, b, c, d, e}, x] && NeQ[b^2 - 4*a*c, 0] && N
eQ[c*d^2 - b*d*e + a*e^2, 0] && IGtQ[p, 0] && LtQ[q, -1]

Rule 1251

Int[(x_)^(m_.)*((d_) + (e_.)*(x_)^2)^(q_.)*((a_) + (b_.)*(x_)^2 + (c_.)*(x_)^4)^(p_.), x_Symbol] :> Dist[1/2,
Subst[Int[x^((m - 1)/2)*(d + e*x)^q*(a + b*x + c*x^2)^p, x], x, x^2], x] /; FreeQ[{a, b, c, d, e, p, q}, x] &&
IntegerQ[(m - 1)/2]

Rubi steps

\begin {align*} \int \frac {a+b x^2+c x^4}{x^5 \sqrt {d-e x} \sqrt {d+e x}} \, dx &=\frac {\sqrt {d^2-e^2 x^2} \int \frac {a+b x^2+c x^4}{x^5 \sqrt {d^2-e^2 x^2}} \, dx}{\sqrt {d-e x} \sqrt {d+e x}}\\ &=\frac {\sqrt {d^2-e^2 x^2} \operatorname {Subst}\left (\int \frac {a+b x+c x^2}{x^3 \sqrt {d^2-e^2 x}} \, dx,x,x^2\right )}{2 \sqrt {d-e x} \sqrt {d+e x}}\\ &=-\frac {\sqrt {d^2-e^2 x^2} \operatorname {Subst}\left (\int \frac {\frac {c d^4+b d^2 e^2+a e^4}{e^4}-\frac {\left (2 c d^2+b e^2\right ) x^2}{e^4}+\frac {c x^4}{e^4}}{\left (\frac {d^2}{e^2}-\frac {x^2}{e^2}\right )^3} \, dx,x,\sqrt {d^2-e^2 x^2}\right )}{e^2 \sqrt {d-e x} \sqrt {d+e x}}\\ &=-\frac {a \left (d^2-e^2 x^2\right )}{4 d^2 x^4 \sqrt {d-e x} \sqrt {d+e x}}+\frac {\sqrt {d^2-e^2 x^2} \operatorname {Subst}\left (\int \frac {-3 a-\frac {4 \left (c d^4+b d^2 e^2\right )}{e^4}+\frac {4 c d^2 x^2}{e^4}}{\left (\frac {d^2}{e^2}-\frac {x^2}{e^2}\right )^2} \, dx,x,\sqrt {d^2-e^2 x^2}\right )}{4 d^2 \sqrt {d-e x} \sqrt {d+e x}}\\ &=-\frac {a \left (d^2-e^2 x^2\right )}{4 d^2 x^4 \sqrt {d-e x} \sqrt {d+e x}}-\frac {\left (4 b d^2+3 a e^2\right ) \left (d^2-e^2 x^2\right )}{8 d^4 x^2 \sqrt {d-e x} \sqrt {d+e x}}-\frac {\left (\left (4 b+\frac {8 c d^2}{e^2}+\frac {3 a e^2}{d^2}\right ) \sqrt {d^2-e^2 x^2}\right ) \operatorname {Subst}\left (\int \frac {1}{\frac {d^2}{e^2}-\frac {x^2}{e^2}} \, dx,x,\sqrt {d^2-e^2 x^2}\right )}{8 d^2 \sqrt {d-e x} \sqrt {d+e x}}\\ &=-\frac {a \left (d^2-e^2 x^2\right )}{4 d^2 x^4 \sqrt {d-e x} \sqrt {d+e x}}-\frac {\left (4 b d^2+3 a e^2\right ) \left (d^2-e^2 x^2\right )}{8 d^4 x^2 \sqrt {d-e x} \sqrt {d+e x}}-\frac {\left (8 c d^4+4 b d^2 e^2+3 a e^4\right ) \sqrt {d^2-e^2 x^2} \tanh ^{-1}\left (\frac {\sqrt {d^2-e^2 x^2}}{d}\right )}{8 d^5 \sqrt {d-e x} \sqrt {d+e x}}\\ \end {align*}

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Mathematica [A]  time = 0.16, size = 134, normalized size = 1.06 \[ \frac {-\left (x^4 \sqrt {d^2-e^2 x^2} \tanh ^{-1}\left (\frac {\sqrt {d^2-e^2 x^2}}{d}\right ) \left (3 a e^4+4 b d^2 e^2+8 c d^4\right )\right )-d \left (d^2-e^2 x^2\right ) \left (2 a d^2+3 a e^2 x^2+4 b d^2 x^2\right )}{8 d^5 x^4 \sqrt {d-e x} \sqrt {d+e x}} \]

Antiderivative was successfully verified.

[In]

Integrate[(a + b*x^2 + c*x^4)/(x^5*Sqrt[d - e*x]*Sqrt[d + e*x]),x]

[Out]

(-(d*(d^2 - e^2*x^2)*(2*a*d^2 + 4*b*d^2*x^2 + 3*a*e^2*x^2)) - (8*c*d^4 + 4*b*d^2*e^2 + 3*a*e^4)*x^4*Sqrt[d^2 -
e^2*x^2]*ArcTanh[Sqrt[d^2 - e^2*x^2]/d])/(8*d^5*x^4*Sqrt[d - e*x]*Sqrt[d + e*x])

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fricas [A]  time = 0.80, size = 102, normalized size = 0.81 \[ \frac {{\left (8 \, c d^{4} + 4 \, b d^{2} e^{2} + 3 \, a e^{4}\right )} x^{4} \log \left (\frac {\sqrt {e x + d} \sqrt {-e x + d} - d}{x}\right ) - {\left (2 \, a d^{3} + {\left (4 \, b d^{3} + 3 \, a d e^{2}\right )} x^{2}\right )} \sqrt {e x + d} \sqrt {-e x + d}}{8 \, d^{5} x^{4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x^4+b*x^2+a)/x^5/(-e*x+d)^(1/2)/(e*x+d)^(1/2),x, algorithm="fricas")

[Out]

1/8*((8*c*d^4 + 4*b*d^2*e^2 + 3*a*e^4)*x^4*log((sqrt(e*x + d)*sqrt(-e*x + d) - d)/x) - (2*a*d^3 + (4*b*d^3 + 3
*a*d*e^2)*x^2)*sqrt(e*x + d)*sqrt(-e*x + d))/(d^5*x^4)

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giac [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: NotImplementedError} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x^4+b*x^2+a)/x^5/(-e*x+d)^(1/2)/(e*x+d)^(1/2),x, algorithm="giac")

[Out]

Exception raised: NotImplementedError >> Unable to parse Giac output: schur row 1 1.55494e-10Francis algorithm
not precise enough for[1.0,-220.862474643,10162.5484803,-174574.213802,1032773.91614]schur row 1 3.66198e-10F
rancis algorithm not precise enough for[1.0,-467.909596927,45612.3731035,-1659969.6644,20804885.8013]Bad condi
tionned root j= 2 value 38.9905751966 ratio 0.000133135092941 mindist 0.002415226181251/exp(1)*(1/2*(-5*a*(2*s
qrt(d+x*exp(1))/(2*sqrt(2)*sqrt(d)-2*sqrt(-d-x*exp(1)+2*d))-1/2*(2*sqrt(2)*sqrt(d)-2*sqrt(-d-x*exp(1)+2*d))/sq
rt(d+x*exp(1)))^7*exp(1)^5-4*b*d^2*(2*sqrt(d+x*exp(1))/(2*sqrt(2)*sqrt(d)-2*sqrt(-d-x*exp(1)+2*d))-1/2*(2*sqrt
(2)*sqrt(d)-2*sqrt(-d-x*exp(1)+2*d))/sqrt(d+x*exp(1)))^7*exp(1)^3-12*a*(2*sqrt(d+x*exp(1))/(2*sqrt(2)*sqrt(d)-
2*sqrt(-d-x*exp(1)+2*d))-1/2*(2*sqrt(2)*sqrt(d)-2*sqrt(-d-x*exp(1)+2*d))/sqrt(d+x*exp(1)))^5*exp(1)^5+16*b*d^2
*(2*sqrt(d+x*exp(1))/(2*sqrt(2)*sqrt(d)-2*sqrt(-d-x*exp(1)+2*d))-1/2*(2*sqrt(2)*sqrt(d)-2*sqrt(-d-x*exp(1)+2*d
))/sqrt(d+x*exp(1)))^5*exp(1)^3-48*a*(2*sqrt(d+x*exp(1))/(2*sqrt(2)*sqrt(d)-2*sqrt(-d-x*exp(1)+2*d))-1/2*(2*sq
rt(2)*sqrt(d)-2*sqrt(-d-x*exp(1)+2*d))/sqrt(d+x*exp(1)))^3*exp(1)^5+64*b*d^2*(2*sqrt(d+x*exp(1))/(2*sqrt(2)*sq
rt(d)-2*sqrt(-d-x*exp(1)+2*d))-1/2*(2*sqrt(2)*sqrt(d)-2*sqrt(-d-x*exp(1)+2*d))/sqrt(d+x*exp(1)))^3*exp(1)^3-32
0*a*(2*sqrt(d+x*exp(1))/(2*sqrt(2)*sqrt(d)-2*sqrt(-d-x*exp(1)+2*d))-1/2*(2*sqrt(2)*sqrt(d)-2*sqrt(-d-x*exp(1)+
2*d))/sqrt(d+x*exp(1)))*exp(1)^5-256*b*d^2*(2*sqrt(d+x*exp(1))/(2*sqrt(2)*sqrt(d)-2*sqrt(-d-x*exp(1)+2*d))-1/2
*(2*sqrt(2)*sqrt(d)-2*sqrt(-d-x*exp(1)+2*d))/sqrt(d+x*exp(1)))*exp(1)^3)/d^5/((2*sqrt(d+x*exp(1))/(2*sqrt(2)*s
qrt(d)-2*sqrt(-d-x*exp(1)+2*d))-1/2*(2*sqrt(2)*sqrt(d)-2*sqrt(-d-x*exp(1)+2*d))/sqrt(d+x*exp(1)))^2-4)^4-1/8*(
3*a*exp(1)^5+4*b*d^2*exp(1)^3+8*c*d^4*exp(1))*ln(abs(2*sqrt(d+x*exp(1))/(2*sqrt(2)*sqrt(d)-2*sqrt(-d-x*exp(1)+
2*d))-1/2*(2*sqrt(2)*sqrt(d)-2*sqrt(-d-x*exp(1)+2*d))/sqrt(d+x*exp(1))+2))/d^5+1/8*(3*a*exp(1)^5+4*b*d^2*exp(1
)^3+8*c*d^4*exp(1))*ln(abs(2*sqrt(d+x*exp(1))/(2*sqrt(2)*sqrt(d)-2*sqrt(-d-x*exp(1)+2*d))-1/2*(2*sqrt(2)*sqrt(
d)-2*sqrt(-d-x*exp(1)+2*d))/sqrt(d+x*exp(1))-2))/d^5)

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maple [C]  time = 0.03, size = 222, normalized size = 1.76 \[ -\frac {\sqrt {-e x +d}\, \sqrt {e x +d}\, \left (3 a \,e^{4} x^{4} \ln \left (\frac {2 \left (d +\sqrt {-e^{2} x^{2}+d^{2}}\, \mathrm {csgn}\relax (d )\right ) d}{x}\right )+4 b \,d^{2} e^{2} x^{4} \ln \left (\frac {2 \left (d +\sqrt {-e^{2} x^{2}+d^{2}}\, \mathrm {csgn}\relax (d )\right ) d}{x}\right )+8 c \,d^{4} x^{4} \ln \left (\frac {2 \left (d +\sqrt {-e^{2} x^{2}+d^{2}}\, \mathrm {csgn}\relax (d )\right ) d}{x}\right )+3 \sqrt {-e^{2} x^{2}+d^{2}}\, a d \,e^{2} x^{2} \mathrm {csgn}\relax (d )+4 \sqrt {-e^{2} x^{2}+d^{2}}\, b \,d^{3} x^{2} \mathrm {csgn}\relax (d )+2 \sqrt {-e^{2} x^{2}+d^{2}}\, a \,d^{3} \mathrm {csgn}\relax (d )\right ) \mathrm {csgn}\relax (d )}{8 \sqrt {-e^{2} x^{2}+d^{2}}\, d^{5} x^{4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*x^4+b*x^2+a)/x^5/(-e*x+d)^(1/2)/(e*x+d)^(1/2),x)

[Out]

-1/8*(-e*x+d)^(1/2)*(e*x+d)^(1/2)/d^5*(3*ln(2*(d+(-e^2*x^2+d^2)^(1/2)*csgn(d))*d/x)*x^4*a*e^4+4*ln(2*(d+(-e^2*
x^2+d^2)^(1/2)*csgn(d))*d/x)*x^4*b*d^2*e^2+8*ln(2*(d+(-e^2*x^2+d^2)^(1/2)*csgn(d))*d/x)*x^4*c*d^4+3*csgn(d)*x^
2*a*d*e^2*(-e^2*x^2+d^2)^(1/2)+4*csgn(d)*x^2*b*d^3*(-e^2*x^2+d^2)^(1/2)+2*csgn(d)*a*d^3*(-e^2*x^2+d^2)^(1/2))*
csgn(d)/(-e^2*x^2+d^2)^(1/2)/x^4

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maxima [A]  time = 1.03, size = 193, normalized size = 1.53 \[ -\frac {c \log \left (\frac {2 \, d^{2}}{{\left | x \right |}} + \frac {2 \, \sqrt {-e^{2} x^{2} + d^{2}} d}{{\left | x \right |}}\right )}{d} - \frac {b e^{2} \log \left (\frac {2 \, d^{2}}{{\left | x \right |}} + \frac {2 \, \sqrt {-e^{2} x^{2} + d^{2}} d}{{\left | x \right |}}\right )}{2 \, d^{3}} - \frac {3 \, a e^{4} \log \left (\frac {2 \, d^{2}}{{\left | x \right |}} + \frac {2 \, \sqrt {-e^{2} x^{2} + d^{2}} d}{{\left | x \right |}}\right )}{8 \, d^{5}} - \frac {\sqrt {-e^{2} x^{2} + d^{2}} b}{2 \, d^{2} x^{2}} - \frac {3 \, \sqrt {-e^{2} x^{2} + d^{2}} a e^{2}}{8 \, d^{4} x^{2}} - \frac {\sqrt {-e^{2} x^{2} + d^{2}} a}{4 \, d^{2} x^{4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x^4+b*x^2+a)/x^5/(-e*x+d)^(1/2)/(e*x+d)^(1/2),x, algorithm="maxima")

[Out]

-c*log(2*d^2/abs(x) + 2*sqrt(-e^2*x^2 + d^2)*d/abs(x))/d - 1/2*b*e^2*log(2*d^2/abs(x) + 2*sqrt(-e^2*x^2 + d^2)
*d/abs(x))/d^3 - 3/8*a*e^4*log(2*d^2/abs(x) + 2*sqrt(-e^2*x^2 + d^2)*d/abs(x))/d^5 - 1/2*sqrt(-e^2*x^2 + d^2)*
b/(d^2*x^2) - 3/8*sqrt(-e^2*x^2 + d^2)*a*e^2/(d^4*x^2) - 1/4*sqrt(-e^2*x^2 + d^2)*a/(d^2*x^4)

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mupad [B]  time = 10.82, size = 932, normalized size = 7.40 \[ \frac {\frac {a\,e^4}{4}+\frac {6\,a\,e^4\,{\left (\sqrt {d+e\,x}-\sqrt {d}\right )}^2}{{\left (\sqrt {d-e\,x}-\sqrt {d}\right )}^2}-\frac {53\,a\,e^4\,{\left (\sqrt {d+e\,x}-\sqrt {d}\right )}^4}{2\,{\left (\sqrt {d-e\,x}-\sqrt {d}\right )}^4}-\frac {87\,a\,e^4\,{\left (\sqrt {d+e\,x}-\sqrt {d}\right )}^6}{{\left (\sqrt {d-e\,x}-\sqrt {d}\right )}^6}+\frac {657\,a\,e^4\,{\left (\sqrt {d+e\,x}-\sqrt {d}\right )}^8}{4\,{\left (\sqrt {d-e\,x}-\sqrt {d}\right )}^8}-\frac {121\,a\,e^4\,{\left (\sqrt {d+e\,x}-\sqrt {d}\right )}^{10}}{{\left (\sqrt {d-e\,x}-\sqrt {d}\right )}^{10}}}{\frac {256\,d^5\,{\left (\sqrt {d+e\,x}-\sqrt {d}\right )}^4}{{\left (\sqrt {d-e\,x}-\sqrt {d}\right )}^4}-\frac {1024\,d^5\,{\left (\sqrt {d+e\,x}-\sqrt {d}\right )}^6}{{\left (\sqrt {d-e\,x}-\sqrt {d}\right )}^6}+\frac {1536\,d^5\,{\left (\sqrt {d+e\,x}-\sqrt {d}\right )}^8}{{\left (\sqrt {d-e\,x}-\sqrt {d}\right )}^8}-\frac {1024\,d^5\,{\left (\sqrt {d+e\,x}-\sqrt {d}\right )}^{10}}{{\left (\sqrt {d-e\,x}-\sqrt {d}\right )}^{10}}+\frac {256\,d^5\,{\left (\sqrt {d+e\,x}-\sqrt {d}\right )}^{12}}{{\left (\sqrt {d-e\,x}-\sqrt {d}\right )}^{12}}}-\frac {\frac {b\,e^2\,{\left (\sqrt {d+e\,x}-\sqrt {d}\right )}^2}{{\left (\sqrt {d-e\,x}-\sqrt {d}\right )}^2}-\frac {b\,e^2}{2}+\frac {15\,b\,e^2\,{\left (\sqrt {d+e\,x}-\sqrt {d}\right )}^4}{2\,{\left (\sqrt {d-e\,x}-\sqrt {d}\right )}^4}}{\frac {16\,d^3\,{\left (\sqrt {d+e\,x}-\sqrt {d}\right )}^2}{{\left (\sqrt {d-e\,x}-\sqrt {d}\right )}^2}-\frac {32\,d^3\,{\left (\sqrt {d+e\,x}-\sqrt {d}\right )}^4}{{\left (\sqrt {d-e\,x}-\sqrt {d}\right )}^4}+\frac {16\,d^3\,{\left (\sqrt {d+e\,x}-\sqrt {d}\right )}^6}{{\left (\sqrt {d-e\,x}-\sqrt {d}\right )}^6}}+\frac {c\,\left (\ln \left (\frac {{\left (\sqrt {d+e\,x}-\sqrt {d}\right )}^2}{{\left (\sqrt {d-e\,x}-\sqrt {d}\right )}^2}-1\right )-\ln \left (\frac {\sqrt {d+e\,x}-\sqrt {d}}{\sqrt {d-e\,x}-\sqrt {d}}\right )\right )}{d}-\frac {3\,a\,e^4\,\ln \left (\frac {\sqrt {d+e\,x}-\sqrt {d}}{\sqrt {d-e\,x}-\sqrt {d}}\right )}{8\,d^5}-\frac {b\,e^2\,\ln \left (\frac {\sqrt {d+e\,x}-\sqrt {d}}{\sqrt {d-e\,x}-\sqrt {d}}\right )}{2\,d^3}+\frac {3\,a\,e^4\,\ln \left (\frac {{\left (\sqrt {d+e\,x}-\sqrt {d}\right )}^2}{{\left (\sqrt {d-e\,x}-\sqrt {d}\right )}^2}-1\right )}{8\,d^5}+\frac {b\,e^2\,\ln \left (\frac {{\left (\sqrt {d+e\,x}-\sqrt {d}\right )}^2}{{\left (\sqrt {d-e\,x}-\sqrt {d}\right )}^2}-1\right )}{2\,d^3}+\frac {7\,a\,e^4\,{\left (\sqrt {d+e\,x}-\sqrt {d}\right )}^2}{256\,d^5\,{\left (\sqrt {d-e\,x}-\sqrt {d}\right )}^2}+\frac {a\,e^4\,{\left (\sqrt {d+e\,x}-\sqrt {d}\right )}^4}{1024\,d^5\,{\left (\sqrt {d-e\,x}-\sqrt {d}\right )}^4}+\frac {b\,e^2\,{\left (\sqrt {d+e\,x}-\sqrt {d}\right )}^2}{32\,d^3\,{\left (\sqrt {d-e\,x}-\sqrt {d}\right )}^2} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + b*x^2 + c*x^4)/(x^5*(d + e*x)^(1/2)*(d - e*x)^(1/2)),x)

[Out]

((a*e^4)/4 + (6*a*e^4*((d + e*x)^(1/2) - d^(1/2))^2)/((d - e*x)^(1/2) - d^(1/2))^2 - (53*a*e^4*((d + e*x)^(1/2
) - d^(1/2))^4)/(2*((d - e*x)^(1/2) - d^(1/2))^4) - (87*a*e^4*((d + e*x)^(1/2) - d^(1/2))^6)/((d - e*x)^(1/2)
- d^(1/2))^6 + (657*a*e^4*((d + e*x)^(1/2) - d^(1/2))^8)/(4*((d - e*x)^(1/2) - d^(1/2))^8) - (121*a*e^4*((d +
e*x)^(1/2) - d^(1/2))^10)/((d - e*x)^(1/2) - d^(1/2))^10)/((256*d^5*((d + e*x)^(1/2) - d^(1/2))^4)/((d - e*x)^
(1/2) - d^(1/2))^4 - (1024*d^5*((d + e*x)^(1/2) - d^(1/2))^6)/((d - e*x)^(1/2) - d^(1/2))^6 + (1536*d^5*((d +
e*x)^(1/2) - d^(1/2))^8)/((d - e*x)^(1/2) - d^(1/2))^8 - (1024*d^5*((d + e*x)^(1/2) - d^(1/2))^10)/((d - e*x)^
(1/2) - d^(1/2))^10 + (256*d^5*((d + e*x)^(1/2) - d^(1/2))^12)/((d - e*x)^(1/2) - d^(1/2))^12) - ((b*e^2*((d +
e*x)^(1/2) - d^(1/2))^2)/((d - e*x)^(1/2) - d^(1/2))^2 - (b*e^2)/2 + (15*b*e^2*((d + e*x)^(1/2) - d^(1/2))^4)
/(2*((d - e*x)^(1/2) - d^(1/2))^4))/((16*d^3*((d + e*x)^(1/2) - d^(1/2))^2)/((d - e*x)^(1/2) - d^(1/2))^2 - (3
2*d^3*((d + e*x)^(1/2) - d^(1/2))^4)/((d - e*x)^(1/2) - d^(1/2))^4 + (16*d^3*((d + e*x)^(1/2) - d^(1/2))^6)/((
d - e*x)^(1/2) - d^(1/2))^6) + (c*(log(((d + e*x)^(1/2) - d^(1/2))^2/((d - e*x)^(1/2) - d^(1/2))^2 - 1) - log(
((d + e*x)^(1/2) - d^(1/2))/((d - e*x)^(1/2) - d^(1/2)))))/d - (3*a*e^4*log(((d + e*x)^(1/2) - d^(1/2))/((d -
e*x)^(1/2) - d^(1/2))))/(8*d^5) - (b*e^2*log(((d + e*x)^(1/2) - d^(1/2))/((d - e*x)^(1/2) - d^(1/2))))/(2*d^3)
+ (3*a*e^4*log(((d + e*x)^(1/2) - d^(1/2))^2/((d - e*x)^(1/2) - d^(1/2))^2 - 1))/(8*d^5) + (b*e^2*log(((d + e
*x)^(1/2) - d^(1/2))^2/((d - e*x)^(1/2) - d^(1/2))^2 - 1))/(2*d^3) + (7*a*e^4*((d + e*x)^(1/2) - d^(1/2))^2)/(
256*d^5*((d - e*x)^(1/2) - d^(1/2))^2) + (a*e^4*((d + e*x)^(1/2) - d^(1/2))^4)/(1024*d^5*((d - e*x)^(1/2) - d^
(1/2))^4) + (b*e^2*((d + e*x)^(1/2) - d^(1/2))^2)/(32*d^3*((d - e*x)^(1/2) - d^(1/2))^2)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x**4+b*x**2+a)/x**5/(-e*x+d)**(1/2)/(e*x+d)**(1/2),x)

[Out]

Timed out

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